Hector Santos wrote:
No. He assumes USER1 will NOT be getting the message, and never will, so
there's no point in retrying it.
D, continue to try USER2, as that transaction was delayed.
Glenn's answer assumes USER1 will be getting the message here.
He believes (as I do) that you can't assume the same about USER2, so you
should retry that.
I'm 100% with Glenn here.
I think a single message delivery attempt with N (N>1) recipients should
behave exactly identically to N delivery attempts each with a single
recipient. Glenn's method works for that, yours doesn't.
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