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Re: changing node names in XML

2002-10-26 04:08:05
<xsl:template match="employee[count(child::*)&gt;0]">
<xsl:template match="employee[count(child::*)=0]">
I'm sure there are better ways ...

The following could have been better..
 <xsl:template match="employee[node()]">
 <xsl:template match="employee[not(node())]">
or
 <xsl:template match="employee[*]">
 <xsl:template match="employee[not(*)]">

We had a discussion some time back regarding which is the best way to check
if there are any child elements..
counting the number of child nodes is not the best way of checking it.

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if you go
test="count(*)=0">
then the semantics of count(*) would seem to imply that the system need
check exactly how many there are (which may take longer of there are
1000000001 of them. On the other hand the chances are that your system
will optimise both of these expressions to some internal system-specific
test-if-empty function and so it probably doesn't make any difference
what you do.

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Cheers
Vasu

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