I have a simple document:
<?xml version="1.0"?>
<doc>
<body>
<div id="header">
<h1>TakePart</h1>
</div>
</body>
</doc>
I want to produce a strict xhtml document and use the following stylesheet:
<?xml version="1.0" ?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns="http://www.w3.org/1999/xhtml";>
<xsl:output method="xml"
doctype-public="-//W3C//DTD XHTML 1 Strict//EN"
doctype-system="http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"/>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="doc">
<html>
<xsl:apply-templates select="@*|node()"/>
</html>
</xsl:template>
</xsl:stylesheet>
What I get is
<?xml version="1.0" encoding="UTF-16"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd";>
<html xmlns="http://www.w3.org/1999/xhtml";>
<body xmlns="">
<div id="header"><h1>TakePart</h1></div>
</body>
</html>
This is correct, since the html output element has the default namespace,
whereas the body element outputted through the identity transform has no
namespace. I get the null namespace on any elements passing through the
identity transform.
How can I design an identity transform that applies the default namespace to
the output? I prefer not to have to restructure my input, and I want all
output nodes to use the strict xhtml namespace. I substituted the above
identity transform with the following and this seems to produce the correct
output, but is this the most efficient way of doing it?
<xsl:template match="*">
<xsl:element name="{name()}">
<xsl:apply-templates select="@*|node()"/>
</xsl:element>
</xsl:template>
<xsl:template match="@*">
<xsl:attribute name="{name()}">
<xsl:value-of select="."/>
</xsl:attribute>
</xsl:template>
Many thanks,
James Carlyle
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list