First of all, thanks a lot to J?rg for pointing me to the Muenchian
method.Relentlessly learning.
I have another question : I would like to get the Xpath value of the current
node. I am done some homework and tried this method suggested by Jeni Tennison
:
? To get an XPath that's guaranteed to be unique, you need to use the index of
the element within its parent rather than its attributevalues. An easy way is
to use recursion with the ancestor-or-self axis:
<xsl:for-each select="ancestor-or-self::*">
<xsl:text />/<xsl:value-of select="name()" />
<xsl:text />[<xsl:number />]<xsl:text />
</xsl:for-each>
Cheers,
Jeni ?
Unfortunately, this does not print any number between the square brackets (with
Xalan). I thought of adding value="position()", but this would be the position
within this context (the for-each), not very useful.
Any suggestion to solve what would be useful debugging information (in my case)
?
Thanks
Louis
--
__________________________________________________________
Sign-up for your own FREE Personalized E-mail at Mail.com
http://www.mail.com/?sr=signup
"Free price comparison tool gives you the best prices and cash back!"
http://www.bestbuyfinder.com/download.htm
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list