In the inner for-each, instead of
xsl:for-each select="key('k', @type)"
try
xsl:for-each select="key('k', @type)[position()!=1]"
Michael Kay
Software AG
home: Michael(_dot_)H(_dot_)Kay(_at_)ntlworld(_dot_)com
work: Michael(_dot_)Kay(_at_)softwareag(_dot_)com
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Lorenzo De Tomasi
Sent: 23 February 2003 23:55
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] different first element in a list
on 23-02-2003 23:08, Michael Kay at
michael(_dot_)h(_dot_)kay(_at_)ntlworld(_dot_)com wrote:
It is displaying the first row twice because you have asked it to.
Your logic is
for-each language that is the first of its @type
display the language
for each language of this @type
display the language
Just remove the code corresponding to the outer "display the
language".
But how can I display each language of this type except the
first? If I remove the code corresponding to the outer
"display the language" I don't understand what's the code
that indicates where to put the language of this @type except
the first :(
The logic I want is:
for-each language that is the first of its @type
label: display the language
for each language of this @type except the first
display the language
What I want to obtain is
1. If in the Xml I have a single 'mother tongue' and a single 'other
tongue':
______________________________________________
mother tongue Italian
other tongue English speak: good
read: excellent
write: good
______________________________________________
2. If in the Xml I have more 'mother tongue's and 'other tongue's:
______________________________________________
mother tongues German
Italian
other tongues English speak: good
read: excellent
write: good
Français speak: basic
read: basic
write: basic
______________________________________________
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