xsl-list
[Top] [All Lists]

Re: Can one _generate_ namespace nodes?

2003-02-22 04:32:35
In XSLT 1.0 the usual circumvention is to create an RTF containing the
required namespace node, and then copy it (which requires xx:node-set):

<xsl:variable name="dummy">
 <xsl:element name="{$prefix}:xxx" namespace="{$uri}"/>
</xsl:variable>

...

<xsl:copy-of
  select="xx:node-set($dummy)/*/namespace::*[name()=$prefix]"/>

Copying of namespace nodes is defined by an erratum to XSLT 1.0.

In case the prefix and the namespace-uri are known in advance, the namespace
declaration can be put within the xsl:stylesheet element.

This will avoid the need to create an RTF -- just use:

<xsl:copy-of select="document('')/*/namespace::*[name()=$prefix]"/>


=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL





 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list