RE: I need to sort and then display only the first 12 entries of a node

I did a foreach, and sorted inside that and did an if (position) type
thing...

I am not sure why this worked...  Why the position reflects differntly
inside the foreach...  But it works so what the heck :)

-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of 
Bill Chmura
Sent: Tuesday, February 11, 2003 5:33 PM
To: XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] I need to sort and then display only the first 12 entries
of a node set



Hello and please help me!

I have a list that I need to sort and then display only the first 12,
then in another one I need to sort and then display all the ones over
12...

It is for a generating a page of recent entries, then a page of past
entries...


I tried this...
------------------------------------------
        <xsl:apply-templates
select="/Shsmith/Newsletters/Newsletter[position() &lt; 12]">
                <xsl:sort select="@dateposted" data-type="text"
order="descending"/> 
        </xsl:apply-templates>
        
        <xsl:apply-templates
select="/Shsmith/Newsletters/Newsletter[position() = 12]"
mode="archivelink">
                <xsl:sort select="@dateposted" data-type="text"
order="descending"/> 
        </xsl:apply-templates>
-----------------------------------------

Which worked fine until I added a new one.  The position takes effect
before the sort which is the reverse of what I need...

So how can I sort it by the dateposted then only process the first 12 of
them...

Any help would be appreciated, be it a solution or thoery for a possible
solution...

Thanks

Bill


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