Hi all,
Is it possible to print out the full path of a node with XSL?
Let say I have a menu.xml like the following for a web application's
menu system:
<menu href="/" label="Home">
<menu href="manage/" label="Manage">
<menu href="customer/" label="Customer">
<menu href="customer/register/" label="Register" />
<menu href="customer/" label="Query" />
</menu>
<menu href="project/" label="Project">
<menu href="project/register/" label="Register" />
<menu href="project/" label="Query" />
</menu>
<menu href="employee/" label="Employee">
<menu href="employee/register/" label="Register" />
<menu href="employee/" label="Query" />
</menu>
</menu>
</menu>
When I view the "Register A Project" page in the web application I
want to print out:
Home :: Manage :: Project :: Register
at the top of the page.
I tried writing several XSLs but most of them got stuck in infinite
recursive loop or prints only the root node or the "Project Register"
node. I just started learning XSL 2 days ago so I'm still not used to
thinking in terms of XPath and XSL.
I would really appreciate any suggestions and/or pointers. Thanks.
Ronny
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list