Hello charles
I am sorry there was a typo there.
I forgot to declare the paramenters. thanks for ###2
but with ###3 even if there is call-template
mentioned.. it works fine for one.(generates ids) but
I want to use the same id that has been generated at
other place where there is tempperid. what should I
type over there so that the same id that I am
generating can be used at ####2
###1 still not known :(
just to give you an overview, I am trying to seperate
authors from the publication data. so that I can
import it in the database as a publication table and
persons table.
Jinesh
--- Charles White <chuck(_at_)tumeric(_dot_)net> wrote:
Hi Jinesh:
You have a couple things going on here with the
structure of your XSLT.
First, you didn't declare your parameters anywhere,
at least not in the code
you provided here.
So, in answer to ######2, the first part of your
author template should
look like this:
<xsl:template match="author">
<xsl:param name="temppubid" />
<xsl:param name="tempperid">
<xsl:call-template name="generate-author-id"/>
It seems you were trying to call the template named
generate-author-id,
which is defined elsewhere, but you used the
xsl:template element to attempt
to do so, so I changed this:
<xsl:template name="generate-author-id">
to this
<xsl:call-template name="generate-author-id"/>
in the code above (but not in the originally defined
template named
generate-author-id that you built later in the
stylesheet).
#####3: You took a sort of object-oriented
developer's approach to
concatenation and mistakenly used the plus (+)
operator in the concat
function, where as you should use commas instead:
concat('800000000',$last+$this)
becomes
select="concat('800000000',$last, $this)"
I'm not sure what you are asking about with ####1,
so I'll let someone else
take over there. :-)
Cheers,
Chuck White
Author, Mastering XSLT, Sybex Books
http://www.javertising.com/webtech
http://www.tumeric.net
----- Original Message -----
From: "Jinesh Varia" <jineshresearch(_at_)yahoo(_dot_)com>
To: <XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Wednesday, February 05, 2003 5:20 PM
Subject: [xsl] Generating IDs and seperating
elements
Hello people,
two unique problems:
My XML is
<publication pubid="0002">
<author>steve lawer</author>
........
<publication>
I want my new XML as:
<publication pubid="0002">
........
</publication>
<person perid="100000004"> <!-- new id generation
-->
<personname>steve lawer</personname>
</person>
<pubper> <!-- publication-person intersection -->
<pubid>0002</pubid>
<perid>100000004</perid>
</pubper>
My XSL is:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" indent="yes"/>
<xsl:template match="publication">
<publication>
<xsl:copy-of select="@*|*[not(self::author or
self::editor)]"/> <!-- this is just to cut the
authors
element-->
</publication>
<xsl:if
test="author=not(.=preceding::author|editor)"
<!-- this is so that we get unique authors and
editors: Please comment on this #####1-->
<xsl:apply-templates select="author">
<xsl:with-param name="temppubid" select="@pubid"
/>
</xsl:apply-templates>
</xsl:if>
</xsl:template>
<xsl:template match="author">
<person>
<xsl:attribute name="perid">
<xsl:template name="generate-author-id"> <!--
generating ids -->
</xsl:attribute>
<personname>
<xsl:value-of select="."/>
</personname>
</person>
<pubper>
<pubid>
<xsl:value-of select="$temppubid"/><!-- Why
is
this not printing the parameter that I am sending
#####2 -->
</pubid>
<perid>
<xsl:value-of select="$tempperid"/> <!- I
want to print the id that I just created for
person
over here. Why is this not printing....how to
print
the value ####3-->
</perid>
<persontype>1</persontype>
</pubper>
</xsl:template>
<xsl:template name="generate-author-id">
<xsl:variable name="last"
select="number(preceding::author[(_at_)perid][1]/@perid)"/>
<xsl:variable name="this"
select="count(preceding::author[not(@perid)])+1"/>
<xsl:variable name="temp"
select="concat('800000000',$last+$this)" />
<xsl:value-of
select="substring($temp,string-length($temp)-9)"
/>
<!-- we just want 10-digit IDs -->
<xsl:template>
</xsl:stylesheet>
Please comment on ###1, ###2, ###3
I dont know why is this not working...any help
will be
appreciated
Thanks in advance
jinx
=====
-----------------------------------------------------------------
Jinesh Varia
Graduate Student, Information Systems
Pennsylvania State University
Email: jinesh(_at_)psu(_dot_)edu
-----------------------------------------------------------------
'Self is the author of its actions.'
__________________________________________________
Do you Yahoo!?
Yahoo! Mail Plus - Powerful. Affordable. Sign up
now.
http://mailplus.yahoo.com
XSL-List info and archive:
http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive:
http://www.mulberrytech.com/xsl/xsl-list
=====
-----------------------------------------------------------------
Jinesh Varia
Graduate Student, Information Systems
Pennsylvania State University
Email: jinesh(_at_)psu(_dot_)edu
-----------------------------------------------------------------
'Self is the author of its actions.'
__________________________________________________
Do you Yahoo!?
Yahoo! Mail Plus - Powerful. Affordable. Sign up now.
http://mailplus.yahoo.com
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list