Hello ,
I have a XML as below --
<rootelem>
<tag>
<a>111</a>
<b>222</b>
<c>333</c>
</tag>
<tag>
<a>444</a>
<b>555</b>
<c>666</c>
<total>10</total>
</tag>
<tag>
<a>777</a>
<b>888</b>
<c>999</c>
</tag>
<tag>
<a>abc</a>
<b>def</b>
<c>ghi</c>
</tag>
<tag>
<a>jkl</a>
<b>mno</b>
<c>pqr</c>
<total>13</total>
</tag>
<tag>
<a>stu</a>
<b>vwx</b>
<c>yz0</c>
<total>18</total>
</tag>
</rootelem>
-------------------------------------------------------
I want to write a XSLT which displays serial no.s as
the <tag> TAGs are found
I have written a XSL as below -
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xsl:template match="rootelem/tag">
<xsl:value-of select="count(preceding::tag) + 1"
/>
<xsl:if test="total">
<xsl:value-of select="count(preceding::tag)
+ 1" />
</xsl:if>
</xsl:template>
</xsl:stylesheet>
I want that when <total> tag comes , an extra serial
no. gets generated which is one more than the previous
one. After the serial no. of <total> tag is o/p, the
next serial no. resumes as 1 more than this.
The above stylesheet is generating output as 122345566
. I want the o/p to come as 123456789(this includes
serial no.s for <total> tag).
Regards,
Mukul
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