Hi
Im trying the follwing now
<xsl:template match="*">
<xsl:variable name="path" select="local-name()"/>
<xsl:variable name="doc2" select="document('test.xml')//*[name()=$path]"/>
<xsl:if test="./@value=$doc2/@value">
<xsl:value-of select="local-name()"/> OK
</xsl:if>
<xsl:if test="./@value!=$doc2/@value">
<xsl:value-of select="local-name()"/> not ok
</xsl:if>
<xsl:apply-templates/>
</xsl:template>
But somehow I dont get an output for each local-name?
Do anyone now why?
Best regards
Johan
-----Original Message-----
From: Michael Kay [mailto:mhk(_at_)mhk(_dot_)me(_dot_)uk]
Sent: den 9 april 2003 20:31
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] using xsl on two xml at the same time
<xsl:variable name="doc2" select="document('d:\foo.xml')" />
The argument to the document() function must be a URI, so this should
fail. Though some processors might accept a Windows filename in place of
a URI, they are wrong to do so.
Michael Kay
Software AG
home: Michael(_dot_)H(_dot_)Kay(_at_)ntlworld(_dot_)com
work: Michael(_dot_)Kay(_at_)softwareag(_dot_)com
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