Because I am working with database meta data (tables and columns), this
question could get confusing, so I will change my objects to Crates and
Oranges. I need to list all the Oranges in a Crate, and hyperlink from the
name of each Orange in the list to a table that contains information that
describes the Orange.
Each Crate may have from 1 to more than 100 Oranges. When I list them
alphabetically, in paragraph form, the code looks like this:
<xsl:for-each
select="//Object[(_at_)id=$CrateID]/Relationships/Relationship[Name='Has_Orange']
/ValueList/Value/Reference">
<xsl:sort select="." data-type="text" order="ascending"/>
<xsl:variable name="OrangeName" select="."/>
<xsl:variable name="OrangeID" select="./@Id"/>
<a href="{$OrangeID}"><xsl:value-of select="$OrangeName"/></a>
<xsl:if test="position() != last()">, </xsl:if>
</xsl:for-each>
But this is messy. Instead, I would like to list them in three columns side
by side.
I tried the following:
<table>
<tr>
<xsl:for-each
select="//Object[(_at_)id=$CrateID]/Relationships/Relationship[Name='Has_Orange']
/ValueList/Value/Reference">
<xsl:variable name="OrangeName" select="."/>
<xsl:variable name="OrangeID" select="./@Id"/>
<td>
<a href="{$OrangeID}"><xsl:value-of select="$OrangeName"/></a>
</td>
<xsl:if test="position() mod 3 = 0"> [something here to end a row and
start a new row]</xsl:if>
</xsl:for-each>
</tr>
</table>
But I couldn't make anything work inside the if test, because it doesn't
like to see </tr><tr>.
Is this a ridiculous way to go about it? Any suggestions?
Walter Crockett
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list