Hi Bruce,
I haven't been following this thread, just saw my name mentioned...
Wendell said:
Maybe Mike or Jeni or someone can suggest an easier way to do this in
XSLT 2.0.
There isn't any way of dynamically evaluating strings as XPaths in
XSLT 2.0 -- you still have to generate the stylesheet to do it. But of
course, if you're using Saxon you can use the saxon:evaluate()
extension function.
Maybe use a key?
I'm confused (again!). I'm basically trying to rework some of my
code, in part based around Geert's suggestions, but I can't really
see how to do what I'm wanting to do (which is to be able to work on
content from external files). It seems, for example, that I cannot
use a key on content I want to access via the doc function.
<xsl:variable name="bibrecord" select="doc(concat('bib-data/',
$bibkey, '.mods'))" />
<xsl:key name="biblio" match="$bibrecord//mods:mods" use="@ID" />
The document that's searched when you call the key() function is the
current document at the time of the call. So you should do:
<xsl:key name="biblio" match="mods:mods" use="@ID" />
and then something along the lines of:
<xsl:for-each select="$bibrecord/key('biblio', $bibkey)">
...
</xsl:for-each>
though I think that you need $bibkey to be defined as:
<xsl:variable name="bibkey" select="//db:bilioref/@linkend" />
since the <biblioref> elements can occur anywhere within the (source)
document.
Note that the path "$bibrecord/key('biblio', $bibkey)" is newly
allowed in XPath 2.0, and makes searching documents using keys a whole
lot easier than it used to be.
Cheers,
Jeni
---
Jeni Tennison
http://www.jenitennison.com/