Is it possible to have a group within a group.
Hi, Steve,
You were really close in your code. The concept that you were missing is to
define one xsl:key with two parameters using the concat function.
If you change your key declaration to be
<xsl:key name="byDateAndCountry" match="entry"
use="concat(parent::group/parent::date/text(), country)" />
or more succinctly:
<xsl:key name="byDateAndCountry" match="entry" use="concat(../../text(),
country)" />
You can then call one key indexed by an entry's date as well as country.
A full stylesheet is below. Please let us know if you have any other questions.
This all becomes a lot easier in 2.0 with xsl:for-each-group. Hopefully someone
will post the 2.0 solution so we can see how much simpler it is.
-Peter
<?xml version="1.0" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" omit-xml-declaration="no" indent="yes"
encoding="UTF-8"/>
<xsl:key name="byDateAndCountry" match="entry" use="concat(../../text(),
country)" />
<xsl:template match="/">
<table border="1">
<xsl:apply-templates select="report/table/date"/>
</table>
</xsl:template>
<xsl:template match="date">
<tr>
<td>
<xsl:value-of select="normalize-space(text())" />
</td>
</tr>
<xsl:for-each select="group/entry[generate-id() =
generate-id(key('byDateAndCountry', concat(../../text(), country))[1])]">
<tr>
<td>
<xsl:value-of select="country" />
</td>
</tr>
<tr>
<td>Group</td>
<td>Name</td>
<td>ID</td>
</tr>
<xsl:apply-templates select="key('byDateAndCountry',
concat(../../text(), country))" />
</xsl:for-each>
</xsl:template>
<xsl:template match="entry">
<tr>
<td>
<xsl:value-of select="../@type" />
</td>
<td>
<xsl:value-of select="name" />
</td>
<td>
<xsl:value-of select="id" />
</td>
</tr>
</xsl:template>
</xsl:stylesheet>
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