On 7/29/06, Christian Marc Schmidt <christianmarc(_at_)gmail(_dot_)com> wrote:
I am a newcomer to XML/XSLT and am struggling
with a bit of code in which I am attempting to populate
a six-column table, while allowing an xsl:sort.
Here is a section of my current code:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
...
<table width="970" border="0" cellspacing="0" cellpadding="0">
<xsl:for-each select="xml/work/*[position() mod 6 = 1]">
<tr>
<xsl:apply-templates
select=".|following-sibling::*[position() < 6]" />
</tr>
</xsl:for-each>
</table>
...
The XML structure I've set up looks like this:
<xml>
<work>
<piece>
</piece>
<piece>
</piece>
...
</work>
</xml>
How would I go about adding sort functionality? It seems like it would
be easy enough, yet all of my attempts so far have failed...
Any suggestions would be much appreciated!
<xsl:sort> can be a child of <xsl:apply-templates>, eg:
<xsl:apply-templates select="........">
<xsl:sort select="....."/>
</xsl:apply-templates/>
cheers
andrew
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