Hi,
The XML I have below, I have been successfully using the id function
to generate the output to print out "Technology" as the topic of the
book. However, I would also like to print out the other one,
"Resources" with the display of the result. Since I marked the id only
as tech, how can I actually get it to print out the preceding or
following sibling, without having to mark all the associated ids that
go along with it?
XSLT:
<xsl:template match="book">
<div>
<p>
<span class="booklist">
Topic:
<xsl:call-template name="print"/>
</span>
<xsl:apply-templates/>
</xsl:template>
<xsl:template name="print">
<xsl:choose>
<xsl:when test="count(ancestor::subject) > 1 ">
<xsl:if test="preceding-sibling::subject !=''">
[Also Used for:
<xsl:value-of select="."/>]
</xsl:if>
<xsl:if test="following-sibling::subject !=''">
[Also Used for: <xsl:value-of select="."/>]
</xsl:if>
<xsl:value-of select="id(@topic)"/>
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates select="id(@topic)"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
XML:
[---------- The portion is in the header section 6 levels away from the <book>
<topicList>
<subject xml:id="tech">Technology</subject>
<subject xml:id="res">Resource</subject>
<subject xml:id="progr">Programming Language</subject>
</topicList>
--------------]
<body>
<book topic="tech" rendition="xslt" author="Tennison, Jeni"
title="Beginning XSLT">
<p>New York: Apress, 2002.</p>
<p>The book serves as an introduction to XSLT based on the examples
of a television program set. A resourceful book for those new to the
technology.</p>
</book>
</body>
Desired Output:
<div><p><span class="booklist">Topic: Technology Resource Programming
Language</span>
<p>Tenison, Jeni.</span> Beginning XSLT. New York: Apress, 2002. </p>
<p>The book serves as an introduction to XSLT based on the examples of
a television program set. A resourceful book for those new to the
technology.</p>
Thanks to those who can help out.
Alice
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