Replace
preceding-sibling::*[1]/text()[last()]
with
preceding-sibling::node()[1]
If the preceding sibling is an element node, you'll get its string value
automatically, you don't need to get it's text node children explicitly.
There's also an ends-with() function in 2.0 which might be clearer than
regular expressions for such a simple job.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Sascha Mantscheff [mailto:922492(_at_)gmx(_dot_)de]
Sent: 29 October 2007 21:28
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] How can I test the last preceding text character?
How do I test if the very last character of any preceding
text - be it in a parent or a sibling - has a certain value?
Example:
<a>
This is parent text a not ending with an x.
<d>This ends with an x</d>
<e>This should issue a message.</e>
This is parent text ending with an x </a>
Now I want to know for each child element is if it is
preceded by an "x".
I can check the sibling with
<xsl:if test="matches(preceding-sibling::*[1]/text()[last()],'x\$') ">
<xsl:message>
Element <xsl:value-of select="name()"/> is preceded by an x.
</xsl:message>
</xsl:if>
But I cannot test the surrounding parent content with the
same model because the parent text may surround the child text.
What's the way to do it?
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