[xsl] xalan and replace "regex"

Hello:
Is there any way I can use replace with xalan. I have tried every thing 
possible but couldn't get it to work:
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="2.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; 
xmlns:xalan="http://xml.apache.org/xalan"; 
xmlns:str="http://exslt.org/strings";>
   <xsl:import href="str/str.xsl" />
  
   <xsl:template match="program">
       <xsl:value-of select="replace(.,'public','&lt;KeyWord&gt; pulic 
&lt;/KeyWord&gt;')" />
   </xsl:template>
</xsl:stylesheet>




I need to scan a piece of java code and be able to highlight the words 
based on their meaning. Anyone had luck with xalan regex ??  or 
analyze-string ??

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