So it seems that it's being converted to a string for some reason, so I
try to set the function's return type to as="node()" or as="element()"
(don't know the difference) but now the compiler seems to require an
object to always be returned, a case which I don't know how to handle
(returning () causes compiler complaint too).
Probably what you want is:
element()?
which means that the return type is a sequence of 0 or 1 elements.
--
Cheers,
Dimitre Novatchev
---------------------------------------
Truly great madness cannot be achieved without significant intelligence.
---------------------------------------
To invent, you need a good imagination and a pile of junk
-------------------------------------
Never fight an inanimate object
-------------------------------------
You've achieved success in your field when you don't know whether what
you're doing is work or play
On Mon, Aug 11, 2008 at 10:09 AM, Bordeman, Chris
<Chris(_dot_)Bordeman(_at_)wolterskluwer(_dot_)com> wrote:
Consider this variable and the function it calls:
<variable name="buyerfirstaddressnode"
select="fn:getfirstactiveaddressnode(buyer/Addresses)"/>
<xsl:function name="fn:getfirstactiveaddressnode">
<xsl:param name="addresses"/>
<xsl:if test="$addresses">
<xsl:sequence select="addresses/Address[Sequence=1 and
IsActive=1]"/>
</xsl:if>
</xsl:function>
Now, if I access $buyerfirstaddressnode/StreetName for instance, or any
other member, I get an EMPTY STRING. However, if I simply output the
$buyerfirstaddressnode variable, I get a string that LOOKS like it
contains the address data I want.
So it seems that it's being converted to a string for some reason, so I
try to set the function's return type to as="node()" or as="element()"
(don't know the difference) but now the compiler seems to require an
object to always be returned, a case which I don't know how to handle
(returning () causes compiler complaint too).
Help please?
Chris
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