From: Martin Honnen [mailto:Martin(_dot_)Honnen(_at_)gmx(_dot_)de]
Sent: Wednesday, August 27, 2008 1:56 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Result tree fragment to string?
Houghton,Andrew wrote:
Hmm... could he do something like:
<xsl:variable name="xml">
<xsl:call-template name="serialize-tree">
<xsl:with-param name="nodes" select="$result-tree" />
</xsl:call-template>
</xsl:variable>
<xsl:template name="serialize-tree">
<xsl:param name="nodes" />
<xsl:apply-templates select="$nodes" mode="serialize" />
The above doesn't handle namespaces, processing-instructions,
comments,
or mixed content, but it could be hacked to do so. Is there a reason
why this approach would not work in XSL 1.0 to satisfy his needs?
Yes, the reason is that you can't do the apply-templates on the result
tree fragment, you would first need to convert it to a node-set with an
extension function.
Oops, I thought his result tree was a node set, not a string...
What if he created a recursive template that parsed the XML string to
determine where elements, attributes and text strings occurred?
Andy.
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