Thanks, Colin,
Although the requirements cannot assume how many levels there are between the
root node and the desired node, your solution points me to something like this.
Does this work?
//[name() == "a" and name() == "c"]
--- On Fri, 8/29/08, Colin Paul Adams
<colin(_at_)colina(_dot_)demon(_dot_)co(_dot_)uk> wrote:
From: Colin Paul Adams <colin(_at_)colina(_dot_)demon(_dot_)co(_dot_)uk>
Subject: Re: [xsl] (simple?) xpath question
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Date: Friday, August 29, 2008, 12:22 PM
"Mark" == mark bordelon
<markcbordelon(_at_)yahoo(_dot_)com> writes:
Mark> All *help*! What is the best way to query
xml with xpath
Mark> to get a disjoint nodelist? Specifically i
want to include
Mark> just the root node alongwith a descendent
node. XML:
Mark> <a> <b> <c>
</c> </b> </a> XPATH: //c
Mark> DESIRED RESULT NODELIST: i.e. not this:
<c> </c> but
Mark> rather this: <a> <c>
</c> </a>
One possibility is:
//*[name() != "b"]
It depends on your exact requirements.
--
Colin Adams
Preston Lancashire
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