Re: [xsl] want to display sum of every two records

I thought, this could have been accomplished as follows:

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
                       version="2.0">

  <xsl:output method="xml" indent="yes" />

  <xsl:template match="test">
     <test>
        <xsl:apply-templates select="mezo[1]" />
     </test>
  </xsl:template>

  <xsl:template match="mezo">
      <xsl:copy-of select="." />
      <xsl:if test="(count(preceding-sibling::mezo) + 1) mod 2 eq 0">
         <mezo eazon="BB"><xsl:value-of select=". +
preceding-sibling::mezo[1]" /></mezo>
      </xsl:if>
      <xsl:apply-templates select="following-sibling::mezo[1]" />
  </xsl:template>

</xsl:stylesheet>

If the input document is, as follows:

<test>
  <mezo eazon="AA">200</mezo>
  <mezo eazon="AA">50</mezo>
  <mezo eazon="AA">300</mezo>
  <mezo eazon="AA">50</mezo>
</test>

The output of the above transform is:

<?xml version="1.0" encoding="UTF-8"?>
<test>
   <mezo eazon="AA">200</mezo>
   <mezo eazon="AA">50</mezo>
   <mezo eazon="BB">250</mezo>
   <mezo eazon="AA">300</mezo>
   <mezo eazon="AA">50</mezo>
   <mezo eazon="BB">350</mezo>
</test>

On Mon, Feb 22, 2010 at 1:39 PM, anil kumar 
<anar(_dot_)leti(_at_)gmail(_dot_)com> wrote:
> Hi,
>
>  want to display the column BB as sum of  every two records
>
> my o/p should be like below..
>
> <mezo eazon="AA">200</mezo>
> <mezo eazon="AA">50</mezo>
> <mezo eazon="BB">250</mezo>
> <mezo eazon="AA">300</mezo>
> <mezo eazon="AA">50</mezo>
> <mezo eazon="BB">350</mezo>
>
> iam breaking my head to get the above o/p.
>
> any suggestions ..Can you get it through XSL
>
> Thanks
> Kumar


-- 
Regards,
Mukul Gandhi

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