Re: [xsl] Can a single XPath statement duplicate the functionality of

Hi Ken,
I removed the [1] at the end to get all of the returns, and for the second 
example  a '50' is returned, the @denomination[5] and the default [0]. It is 
clear that the @souvenir-sheet value is ignored in both cases. I am using 
XSLT 2, so it always collapses. Is there something incorrect with
../Location[name(@*)=name(current()/@*)]

It seems correct to me.
Mark

-----Original Message----- 
From: Mark
Sent: Sunday, October 23, 2011 5:39 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Can a single XPath statement duplicate the functionality 
of this verbose  statement?
Hi Ken,
Yes, only one attribute to either element.

You said:
xsl:copy-of select="( ../Location[name(@*)=name(current()/@*)] ,
                    ../Location/@denomination ,
                    '0' )[1]"/>

but I may have explained my needs incorrectly. Your statement works on the
first example below [uses @denomination] but returns nothing for the second
example; there it should return the value of the <Locations
@souvenir-sheet>, i.e., '1'.
Thanks,
Mark

<Stamp>
       <Formats souvenir-sheet="2895"/>
     <Location denomination="1"/>
</Stamp>

<Stamp>
      <Formats souvenir-sheet="2896"/>
     <Location denomination="5"/>
     <Location souvenir-sheet="1"/>
   </Stamp>



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