[xsl] Response to G Ken Holman re Question on search and replace in XSL

Ken,

Thanks so much for your response.  This is something I never would've figured 
out on my own.  I've implemented your suggestions, but I'm getting an error 
message and I'm hoping it's a quick fix.  Here's the code I've got:

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="2.0">

<xsl:output method="html" indent="yes" omit-xml-declaration="yes" />

....other HTML and  <xsl:apply-templates> sections.....
<xsl:apply-templates select="APName" />
....more HTML and <xsl:apply-templates> sections

...other <xsl:template> sections...
<xsl:template match="APName">
    Input value: "<xsl:value-of select="."/>"

<!--create groups of three using the tokenized input-->
<xsl:for-each-group select="tokenize(.,';')" group-by="( position() - 1 ) idiv 
3">
  <!--each group produces a row-->
  <tr>
    <td valign="top" width="180"></td>
    <!--the members of the group make up the remaining columns-->
    <xsl:for-each select="current-group()">
      <td>
        <xsl:value-of select="."/>
      </td>
    </xsl:for-each>
  </tr>
</xsl:for-each-group>
</xsl:template>
...more <xsl:template> sections

I'm getting an error message on the <xsl:for-each-group> statement: 
'xsl:for-each-group' is not a recognized extension element.  I did some 
research and found some suggestions that this would work better with version 
1.0.  When I try that, though, the error message I get is: 'xsl:for-each-group' 
cannot be a child of the 'xsl:template' element.  So, once again, I'm stuck.  
Perhaps it would help if I explain how this code is being used.  It's called 
from an ASP.Net application, and it's used to generate an HTML document which 
is then sent via an SMTP server as an email.  The users are using Windows 7 and 
viewing the application in IE9.  However, they *never* view the output of this 
XSL document; it's just sent as an email behind the scenes.  The .Net code is 
as follows:

protected override void PrepareMessageBody()
                {
                        using (DataSet data = 
DataGateway.getNYConflictNoticeInformation(RequestID)) //this calls a SQL 
Server stored procedure; the DataSet called data contains various fields, 
including the aaa;bbb;ccc;ddd;eee;fff field that we've been dealing with.
                        {
                                data.DataSetName = "CMIntake";
                                data.Tables[0].TableName = "NYConflictNotice";
                                XmlDataDocument xmldoc = new 
XmlDataDocument(data);

                                XslTransform xslt = new XslTransform();
                                string xsltfile = this.TemplatePath + 
ConfigurationSettings.AppSettings["NYConflictNoticeTemplateName"].ToString();  
//the xsltfile is the file we've been dealing with.  There are a number of 
<xsl:apply-templates> sections and a number of <xsl:template> sections, but 
we've only been dealing with the one that formats APName
                                xslt.Load(xsltfile);

                                TextWriter writer = new StringWriter();
                                xslt.Transform(xmldoc, null, writer, null);

                                Message.Body = writer.ToString();
                                Message.BodyFormat = MailFormat.Html; // This 
Message is later sent as an email
                        }

                }

I hope this helps.  If this *isn't* a quick fix, *please* let me know and I'll 
just approach this from a different perspective, i.e., I'll just build an HTML 
document within the C# code and forget about XSL altogether.

Thanks so much for all your help,


Melanie Peterson
Project Coordinator/Systems Developer
Kramer Levin Naftalis & Frankel LLP
1177 Ave. of the Americas
New York, NY 10036
212-715-7738



Melanie S. Peterson

Project Coordinator/Systems Developer
Kramer Levin Naftalis & Frankel LLP
1177 Avenue of the Americas
New York, New York 10036
Tel: 212-715-7738
Fax: 212-715-8000
Email: MPeterson(_at_)KRAMERLEVIN(_dot_)com
<http://www.kramerlevin.com/>


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