At 2012-04-14 22:03 +0200, Leo Studer wrote:
thank you for your lines.
The question came up in class. I teach xPath and asked the students
how to retrieve the first CD of each artist.
Here the xPath 1 which does the job:
//cd[not(artist = preceding-sibling::cd/artist)]
A student asked how to retrieve the newest CD of each artist.
I told the student, that I know how to do that with xPath 2.0 and
gave this solution
for $i in distinct-values(//artist) return (//cd[artist eq
$i and year= max(//cd[artist eq $i ]/year)])
The problem is, that in xPath 1 we have neither "for" nor
"distinct-values()". So I wonder, is it possible to retrieve the
newest cd of each artist with xPath 1 only.
Your proposition with XSLT 1 is nice, thank you.
Forgive me ... when I saw "XPath 1" in the subject line, my thought
was that the only context of using XPath 1 is in XSLT 1 and so
created an example using XSLT.
I wondered about current(), but that is like key() as it is only in
XSLT and not XPath. And even with it I could not figure out how to
get what you want because I end up at cdcatalog and not cd.
I cannot think of a way of getting the newest CD of each artist using
only XPath 1. This is because of not being able to access
information from within the predicate to something known outside of
the step. One needs simultaneous comparisons to two children of the
element and each time I write the predicate I only have access to one.
. . . . . . . . . Ken
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