Nice work. I don't have any node-set() suggestions, just a comment about the
chessboard representation. You don't need to use images at all here. Unicode
actually contains all the characters for chess pieces, at codepoints 2654-265F
(9812-9823). White queen is 2655 (9813) and black queen is 265B (9819). Could
simplify your code a little.
~ Scott
-----Original Message-----
From: Hermann Stamm-Wilbrandt [mailto:STAMMW(_at_)de(_dot_)ibm(_dot_)com]
Sent: Friday, April 20, 2012 5:26 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] XSLT 1.0 n-queens and questions
Hello,
I posted a XSLT 1.0 implementation for n-queens running in all big5 browsers
https://www.ibm.com/developerworks/mydeveloperworks/blogs/HermannSW/entry/n_queens_xsl_xml14
It produces all solutions for 4<=n<=9, nicely grouped.
I have two questions on the solution:
1)
Grouping is done by two solutions considered equivalent if one can be
transformed into the other by rotations and/or mirroring.
I did not find a way to make this "equivalence" available in xsl:key for using
Muenchian grouping -- can anybody think of how Muenchian grouping be used
instead the "handmade" duplicate elimination in n-queens.xsl.xml?
2)
I made much use of exslt:node-set() function although the templates itself use
xsl:call-template and xsl:apply-templates.
Is a more "functional" solution without so many exslt:node-set() calls possible
in XSLT 1.0?
Mit besten Gruessen / Best wishes,
Hermann Stamm-Wilbrandt
Level 3 support for XML Compiler team and Fixpack team lead WebSphere DataPower
SOA Appliances
https://www.ibm.com/developerworks/mydeveloperworks/blogs/HermannSW/
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