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Re: XKCD - Nanobots

2011-02-28 02:58:21

On Feb 28, 2011, at 10:40 AM, Bob Hinden wrote:

Pete,

On Feb 27, 2011, at 11:32 PM, Pete Resnick wrote:

I'm sorry, but how could this *not* be posted to the IETF list?

<http://xkcd.com/865/>

I did a rough calculation and think they would have not run out of IPv6 
addresses :-)

I assumed a nanobot was 1 x 10^-6 M^2 and the surface of the earth was 5.1 x 
10^11 M^2 (from Wikipedia).  This means it would take 5.1 x 10^17 nanobots to 
cover the earth.  The IPv6 address space is 3.4 x 10^38.  Of course, I 
assumed only one layer deep. 

Bob

Yes, but I think the nanobots are supposed to devour the entire earth, so it's 
volume that counts. The volume is about 1x10^21 m^3. So 40% is 4 x 10^20 m^3.  

3.4 x 10^38 nanobots comes to 8.5 x 10^17 nanobots per m^3, or about 1.17 
microns^3 per nanobot.

Sounds about right.


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