Dear UTF-8 regular expression gurus:
$ perl -e '$x = "\x{2019}\nk"; $x =~ s/(\S)\n(\S)/$1 $2/sg; print "$x\n";'
' <= this denotes a \x{2019} followed by \n
k
$ perl -e '$x = "b\nk"; $x =~ s/(\S)\n(\S)/$1 $2/sg; print "$x\n";'
b k
Any idea, why the Unicode apostrophe is not matched by a \S in the first
case, whereas the 'b' is?
A bug? Was seemingly broken still in 5.8.0, but 5.8.1-to-be seems
to get this right. (I don't off-hand remember this particular kind
of problem but there were some s/// fixes that might have helped.)
I'll add this to the test suite so that it stays fixed.
Also note that
$ perl -e 'print (("\x{2019}" =~ /\S/) . "\n");'
1
so \x{2019} *does* match \S in principle ... odd.
(Perl v5.6.0 built for i386-linux)
Markus
--
Markus Kuhn, Computer Lab, Univ of Cambridge, GB
http://www.cl.cam.ac.uk/~mgk25/ | __oo_O..O_oo__
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biologist word we use for 'stable'. It is 'dead'." -- Jack Cohen
