> if have a number of recipes something like this:
>
> -----
> :0
> * ^From.*peter
> $BIGMAILBOX
>
> :0
> * ^From.*alex
> $BIGMAILBOX
>
> :0
> * ^From.*erwin
> $BIGMAILBOX
> ----
>
> All to the same mailbox.
> Does an option exist to change the above recipe into this ?
>
> :0
> * ^From.*peter
> * ^From.*alex
> * ^From.*erwin
> $BIGMAILBOX
>
> Or is there another way to solve this.
As others have pointed out, you can use De Morgan's theorem:
A or B <==> ! (!A and !B )
you can use regexp alternations, like this:
:0
* ^From.*(peter|alex|erwin)
$BIGMAILBOX
regexps work even for complex, completely unrelated headers:
:0
* (^Subject: FREE MONEY|\
^From: .*Spamdex.com|\
^To: a-big-mailing-list-I-dont-like\|
^X-Organization: spam-central)
$BIGMAILBOX
But, you can also use weighted scoring to form an OR condition.
:0
* 1^0 ^From.*peter
* 1^0 ^From.*alex
* 1^0 ^From.*erwin
$BIGMAILBOX
and showing an alternative of the complex one:
:0
* 1^0 ^Subject: FREE MONEY
* 1^0 ^From:.*Spamdex.com
* 1^0 ^To:.*a-big-mailing-list-I-dont-like
* 1^0 ^X-Organization:.*spam-central
$BIGMAILBOX
Please read the man page on "procmailsc" for detailed explanations of
weighted scoring.
Good luck
___________________________________________________________
Alan Stebbens <aks(_at_)sgi(_dot_)com> http://reality.sgi.com/aks