When I suggested,
T> sed -ne 1h -e \$G -e 2,\$p
Bart cautioned me,
S> Gotta be careful there ... some versions of sed don't let you put the -n
S> and the -e in the same argument like that.
OK; I've never run into that. That is a big deficiency, because if they
can't handle -n and -e in one argument, how can they deal with hash-bang
sedfiles that start
#!/usr/bin/sed -nf
given that there can be only one argument to the executable on the hash-bang
line and
#!/usr/bin/sed -n -f
won't be tolerated by the kernel? Will "#n" work on the second line if the
topmost line is the hash-bang? I'd test for myself, but I don't have access
to a version of sed that won't accept -ne and -nf.
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