RE: Data from DB in xsl

Hi,

> on writing the code you gave me, i get the error below:
>
> "Unexpected character in query string. contains($sText,-->\<--n\n)"
>
> here is my code:
>
> <xsl:template name="paragrapher">
>       <xsl:param name="sText"/>
>       <xsl:if test="contains($sText,\n\n)">
>               <p>
>                       <xsl:value-of 
> select="substring-before($sText,\n\n)"/>
>               </p>
>       </xsl:if>
> </xsl:template>
Yes, well, that was pseudo-code - XPath doesn't use \n to denote a LINE FEED 
character. And you missed the else clause, too.

<xsl:template name="paragrapher">
  <xsl:param name="sText"/>
  <xsl:choose>  
    <xsl:when test="contains($sText, '&#xA;&#xA;')">
      <p>
        <xsl:value-of select="substring-before($sText, '&#xA;&#xA;')"/>
      </p>
        <xsl:call-template name="paragrapher">
        <xsl:with-param name="sText" select="substring-after($sText, 
'&#xA;&#xA;')" />
      </xsl:call-template>
    </xsl:when>
    <xsl:otherwise>
      <p>
        <xsl:value-of select="$sText"/>
      </p>
    </xsl:otherwise>
  </xsl:choose>
</xsl:template>

Jarno

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