<xsl:value-of select="translate(string(number($operand1) + number($operand2)),
'2', '1')"/>
cool!
I like very much this implementation, it's much much more efficient than mine
and prevents the stack overflow that may happen with long input strings.
Thanks a lot!
============================== Original Message ==============================
From: Rubén
To: McNally, David
Date: Wednesday, September 25, 2002, 11:34:29 PM
Subject: [xsl] binary-or
I think this does what you want, though I didn't try all your test data.
It's not recursive - if that makes any difference.
<xsl:template name="or">
<xsl:param name="operand1" select="''"/>
<xsl:param name="operand2" select="''"/>
<xsl:variable name="result1">
<!-- would just return this if we didn't need to do the zero
padding -->
<xsl:value-of select="translate(string(number($operand1) +
number($operand2)), '2', '1')"/>
</xsl:variable>
<xsl:choose>
<xsl:when test="string-length($operand1) >
string-length($operand2)">
<xsl:value-of
select="concat(substring($operand1,1,(string-length($operand1) -
string-length($result1))),$result1)"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of
select="concat(substring($operand2,1,(string-length($operand2) -
string-length($result1))),$result1)"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
With some thought the xsl:choose could probable be improved.
HTH
David.
--
David McNally Moody's Investors Service
Software Engineer 99 Church St, NY NY 10007
David(_dot_)McNally(_at_)Moodys(_dot_)com (212) 553-7475
-----Original Message-----
From: Rubén [mailto:rubenm(_at_)telepolis(_dot_)com]
Sent: Wednesday, September 25, 2002 4:35 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] binary-or
Hello list! I couldn't find a "binary-or" (or "mask-or")
operation in XPath 1.1 so I tried to
emulate it with a template. I wrote a recursive
implementation but I'm not very
happy with the result. I wonder if there is a simpler (and
maybe more efficient)
solution. Any suggestions?
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