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RE: a nicer total sibling count than this

2002-09-18 13:05:44
Hi Stewart,

You don't need all the counting stuff. If I understand you correctly, the test 
is simply: "is there a preceding def element?". If so then there must be 2 or 
more defs for the word. I.e. the following template should work just as well:

        <xsl:template match="def">
                <xsl:if test="preceding-sibling::def">
                        <xsl:element name="strong">
                                <xsl:number/>
                                <xsl:text>&#160;</xsl:text>
                        </xsl:element>
                </xsl:if>
                <xsl:apply-templates/>
        </xsl:template>

Hope that helps.

cheers

Malcolm




-----Original Message-----
From: scruss(_at_)sympatico(_dot_)ca [mailto:scruss(_at_)sympatico(_dot_)ca]
Sent: Wednesday, September 18, 2002 2:39 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] a nicer total sibling count than this


I'm working with a dictionary marked up in XML. Conventionally, one numbers 
definitions (def elements here)  only if there are two or more definitions for 
the given part of speech. 

To my surprise and delight, the following worked, producing heavy def numbers 
with a following non-break space:

 <xsl:template match="def">
  <xsl:if test="(count(preceding-sibling::def) +   
                 count(following-sibling::def)) >= 1">
   <xsl:element name="strong">
    <xsl:number/>
    <xsl:text>&#160;</xsl:text>
   </xsl:element>
  </xsl:if>
  <xsl:apply-templates/>
 </xsl:template>

Is there a prettier/more efficient way of doing the same thing without 
resorting to frankly ugly 
'(count(preceding-sibling::def)+count(following-sibling::def))'?

thanks,
 Stewart



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