Hello Will,
you either have to statically change the context to the second document
<xsl:for-each select="document('xml2.xml')/people/person">
<xsl:sort select="turtle"/>
...
</xsl:for-each>
(but I think that's not an option)
or you have to create a temporary tree with all information merged. You
can do this either via a 2 transformations or using an extension
function exslt:node-set(). While extension functions always have the
disadvantage of less portability, exslt is an approach against that
matter (http://www.exslt.org).
<xsl:variable name="persons">
<xsl:for-each select="people/person">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:copy-of select="*"/>
<xsl:variable name="ownerName" select="@name"/>
<xsl:for-each select="document('xml2.xml')">
<xsl:copy-of select="key('turtleByOwner', $ownerName)"
</xsl:for-each>
<xsl:copy-of select="
</xsl:copy>
</xsl:for-each>
</xsl:variable>
<xsl:for-each select="exslt:node-set($persons)/person">
<xsl:sort select="cat"/> <!-- or turtle -->
...
</xsl:for-each>
Other comments to your stylesheet:
Are you sure you want version="2.0"??
In the match attribute of the key, you don't need //. The key indexes
the whole XML tree (so all turtle elements, even without //).
Regards,
Joerg
Carter, Will wrote:
Hi,
I have a sorting problem when I use xsl to combine data from 2 xml files into
one html output.
here is my xml file 1 (xml1.xml):
-----------------------
<people>
<person name="george">
<cat>cat-zoro</cat>
<dog>dog-butch</dog>
<fish>fish-jaws</fish>
</person>
<person name="jennifer">
<cat>cat-felix</cat>
<dog>dog-fido</dog>
<fish>fish-moby</fish>
</person>
<person name="simon">
<cat>cat-tom</cat>
<dog>dog-scooby</dog>
<fish>fish-conroy</fish>
</person>
</people>
-----------------------
here is my xml file 2 (xml2.xml):
-----------------------
<people>
<person name="george">
<turtle>turtle-greeny</turtle>
</person>
<person name="jennifer">
<turtle>turtle-browny</turtle>
</person>
<person name="simon">
<turtle>turtle-red</turtle>
</person>
</people>
-----------------------
here is my stylesheet:
-----------------------
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns="http://www.w3.org/tr/REC-html40"; version="2.0">
<xsl:key name="turtleByOwner" match="//turtle" use="../@name" />
<xsl:template match="/">
<table border="1" cellspacing="0" cellpadding="0">
<xsl:for-each select="people/person">
<xsl:sort select="cat"/>
<tr>
<td colspan="7">Person: <xsl:value-of select="@name"/></td>
</tr>
<tr>
<td><xsl:value-of select="cat"/></td>
<td><xsl:value-of select="dog"/></td>
<td><xsl:value-of select="fish"/></td>
<xsl:variable name="ownerName" select="@name"/>
<td>
<xsl:for-each select="document('xml2.xml')">
<xsl:value-of select="key('turtleByOwner', $ownerName)"
</xsl:for-each>
</td>
</tr>
</xsl:for-each>
</table>
</xsl:template>
</xsl:stylesheet>
-----------------------
this correctly produces (sorted by cat):
-----------------------
Person: jennifer
cat-felix dog-fido fish-moby turtle-browny
Person: simon
cat-tom dog-scooby fish-conroy turtle-red
Person: george
cat-zoro dog-butch fish-jaws turtle-greeny
-----------------------
but I want to sort by turtle (I want this output):
-----------------------
Person: jennifer
cat-felix dog-fido fish-moby turtle-browny
Person: george
cat-zoro dog-butch fish-jaws turtle-greeny
Person: simon
cat-tom dog-scooby fish-conroy turtle-red
-----------------------
I changed the sort line to be:
<xsl:sort select="turtle"/>
but it doesn't work, my output is:
-----------------------
Person: george
cat-zoro dog-butch fish-jaws turtle-greeny
Person: jennifer
cat-felix dog-fido fish-moby turtle-browny
Person: simon
cat-tom dog-scooby fish-conroy turtle-red
-----------------------
how can I sort on the turtle column from the document reference?
thanks for any ideas.
will
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