You need to handle this when processing the <a> element, not when
processing its children, otherwise, as you point out, you will insert
the default <c> element once for each child.
<xsl:template match="a">
<xsl:apply-templates select="*"/>
<xsl:if test="not(c)"><c>0</c></xsl:if>
</xsl:template>
Michael Kay
Software AG
home: Michael(_dot_)H(_dot_)Kay(_at_)ntlworld(_dot_)com
work: Michael(_dot_)Kay(_at_)softwareag(_dot_)com
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Thomas Olausson
Sent: 10 September 2002 01:04
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] insert default node if it doesn't exist
I always have trouble with xslt when processing something once:
Ia certain child doesn't exists, I'd like to insert a default value:
Like the one below. The 2nd 'a' should after processing
include a <c>0</c> (since it doesn't have it).
before:
<data>
<a>
<b>100</b>
<c>120</c>
</a>
<a>
<b>100</b>
<g>300</g>
</a>
</data>
after:
<data>
<a>
<b>100</b>
<c>120</c>
</a>
<a>
<b>100</b>
<g>300</g>
<c>0</c>
</a>
</data>
I've tried with this XSLT. Problem is that since the match
doesn't find <c> for the 2nd both for b and g, I'll get a <c>
for everyone of them. How can this be solved?
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" version="1.0" encoding="UTF-8"
indent="yes"/>
<xsl:template match="a/*">
<xsl:copy>
<xsl:apply-templates
select="@*|node()"/>
</xsl:copy>
<xsl:if test="not(../c)">
<c>0</c>
</xsl:if>
</xsl:template>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
/Thomas
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