thomas wrote:
Hello
first a little german-xml for beginners. ;-)
<frage>=<question>, <antwort>=<answer>
got it? ok!
Im having a problem with the following task.
I want a simple fo:table. Left cell, the question, right cell the answer.
I managed to loop over the <frage> and put the content in a new
row/cell. But how do I get the accordant <antwort> in the SAME loop in
the second cell?
I tried to make 2 loops each and put it in tables next to each other.
The problem is when the content from the right <antwort> table is bigger
than the left <frage> table , the <frage> and <antwort> are not on the
same row.
forgive me my ugly source o great xsl programmers. Im a newbie....
xml:
<page>
<info>
<profil>
<frage>frage 1 frage 1?</frage>
<antwort>antwort 1 antwort 1 antwort 1 antwort 1</antwort>
<frage>frage 2 frage 2?</frage>
<antwort>antwort 2 antwort 2 antwort 2 antwort 2</antwort>
<frage>frage 3 frage 3?</frage>
<antwort>antwort 3 antwort 3 antwort 3 antwort 3</antwort>
<frage>frage 4 frage 4?</frage>
<antwort>antwort 4 antwort 4 antwort 4 antwort 4</antwort>
</profil>
</info>
</page>
The solution will resemble this (HTML tables, but you get the idea):
<xsl:template match="profile">
<table>
<tbody>
<xsl:for-each select="frage">
<tr>
<td>
<xsl:value-of select="."/>
</td>
<td>
<xsl:value-of select="following-sibling::antwort[1]"/>
</td>
</tr>
</xsl:for-each>
</tbody>
</table>
</xsl:template>
Or this (same thing):
<xsl:template match="profile">
<table>
<tbody>
<xsl:apply-templates select="frage"/>
</tbody>
</table>
</xsl:template>
<xsl:template match="frage">
<tr>
<td>
<xsl:value-of select="."/>
</td>
<td>
<xsl:value-of select="following-sibling::antwort[1]"/>
</td>
</tr>
</xsl:template>
- Mike
____________________________________________________________________________
mike j. brown | xml/xslt: http://skew.org/xml/
denver/boulder, colorado, usa | resume: http://skew.org/~mike/resume/
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