If the different elements are in the same substitution group, then you
can match them in XSLT 2.0 by writing
<xsl:template match="*[. instance of element foo]">
where foo is the head element of the substitution group. We are hoping
to come up with better syntax for this, but the functionality is there.
Michael Kay
Software AG
home: Michael(_dot_)H(_dot_)Kay(_at_)ntlworld(_dot_)com
work: Michael(_dot_)Kay(_at_)softwareag(_dot_)com
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Robert Koberg
Sent: 06 September 2002 13:40
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] template's match-set ? (feature request?)
Hi,
[forgive me if this is already available. if so, what is it called?]
I was looking for the following functionality in the draft
for XSLT2, but could not find it. It seems like it is possible.
Anyway, what I want to do is have a 'match-set' (sort of like
attribute-set) that I can 'use-match-set' on various
templates with different modes.
For example:
<xsl:match-set name="content-pieces">
<xsl:match name="article"/>
<xsl:match name="faq"/>
<xsl:match name="job"/>
</xsl:match-set>
<xsl:template use-match-set="content-pieces" mode="mode-1">
<xsl:apply-templates/>
</xsl:template>
<xsl:template use-match-set="content-pieces" mode="mode-2">
<xsl:apply-templates/>
</xsl:template>
<xsl:template use-match-set="content-pieces" mode="mode-n">
<xsl:apply-templates/>
</xsl:template>
This would be useful to me because I am occiasionally adding
new tags to my schema that work the same in the XSLT, in many cases.
Does this exist in some other way? Is this a reasonable
request if it does not?
best,
-Rob
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list