Hello Elke,
if you want to copy all the elements, you have to tell it the processor. You
can't manipulate the input document. At http://www.w3.org/TR/xslt#copying
you can find a template that copies everything to the output. If you want to
add some elements, you must add some more template so that these elements
will not be matched with the general one, but with the specific one:
identity transformation template:
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
specific template:
<xsl:template match="entries">
<xsl:copy>
<xsl:appply-templates select="@*|node()"/>
<entry>a new entry</entry>
</xsl:copy>
</xsl:template>
Hope this helps a bit,
Joerg
Naraschewski, E. wrote:
Hello,
I am just at the beginning using xslt. Right now I am doubting my comprehension
of xslt. I am trying to transform an xml file into another xml file just
wishing to be able to add a new element into my result file. I thought I should
be able to keep all my already existing tags in the result file. Am I wrong?
They all vanish. Is there a way to keep them?
While adding a new element I only get the result <entry/>. Actually I would like to enclose some more elements like this <entry>...</entry>.
The last question is, whether it is possible to ask wether an element is filled or not when
using <xsl:if> or <xsl:choose>.
I am hoping to hearing from you soon.
Best regards
Elke Naraschewski
--
System Development
VIRBUS AG
Fon +49(0)341-979-7419
Fax +49(0)341-979-7409
joerg(_dot_)heinicke(_at_)virbus(_dot_)de
www.virbus.de
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