You're doing it right. If you want to produce an output element whose
name is computed from the name of an input element, but isn't identical
(e.g., in your case, it has the same local name but a different
namespace), then xsl:element is the way to do it.
Michael Kay
Software AG
home: Michael(_dot_)H(_dot_)Kay(_at_)ntlworld(_dot_)com
work: Michael(_dot_)Kay(_at_)softwareag(_dot_)com
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
James Carlyle
Sent: 17 October 2002 18:01
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Namespaces and the identity transform
I have a simple document:
<?xml version="1.0"?>
<doc>
<body>
<div id="header">
<h1>TakePart</h1>
</div>
</body>
</doc>
I want to produce a strict xhtml document and use the
following stylesheet: <?xml version="1.0" ?> <xsl:stylesheet
version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns="http://www.w3.org/1999/xhtml";>
<xsl:output method="xml"
doctype-public="-//W3C//DTD XHTML 1 Strict//EN"
doctype-system="http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"/>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="doc">
<html>
<xsl:apply-templates select="@*|node()"/>
</html>
</xsl:template>
</xsl:stylesheet>
What I get is
<?xml version="1.0" encoding="UTF-16"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-> strict.dtd">
<html
xmlns="http://www.w3.org/1999/xhtml";>
<body xmlns="">
<div id="header"><h1>TakePart</h1></div>
</body>
</html>
This is correct, since the html output element has the
default namespace, whereas the body element outputted through
the identity transform has no namespace. I get the null
namespace on any elements passing through the identity transform.
How can I design an identity transform that applies the
default namespace to the output? I prefer not to have to
restructure my input, and I want all output nodes to use the
strict xhtml namespace. I substituted the above identity
transform with the following and this seems to produce the
correct output, but is this the most efficient way of doing it?
<xsl:template match="*">
<xsl:element name="{name()}">
<xsl:apply-templates select="@*|node()"/>
</xsl:element>
</xsl:template>
<xsl:template match="@*">
<xsl:attribute name="{name()}">
<xsl:value-of select="."/>
</xsl:attribute>
</xsl:template>
Many thanks,
James Carlyle
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list