The simplest way of doing this in XSLT 1.0 is probably to use a
multi-pass transformation. In the first pass, build a temporary tree
containing the computed sort keys. In the second pass (done using
xx:node-set()), do the sort.
In XSLT 2.0 you can compute the sort key using an xsl:function.
Michael Kay
Software AG
home: Michael(_dot_)H(_dot_)Kay(_at_)ntlworld(_dot_)com
work: Michael(_dot_)Kay(_at_)softwareag(_dot_)com
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Scott Bronson
Sent: 26 October 2002 17:58
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Sorting on a transformed string?
Hello. A sort problem is stumping me right now. I've got
the following
nodes:
<Member name="CreateInstance">
<Member name="System.Caption.Insert">
<Member name="System.Collections.ICollection.Count"
I'd like to sort them by name, without leading namespace:
Count, CreateInstance, Insert
Then I'd like to output them, WITH the namespace:
System.Collections.ICollection.Count
CreateInstance
System.Caption.Insert
Normally, I use leaf-name (below) to trim the namespace.
However, I suspect it's impossible to get sort to use a named
template, and I haven't figured out any other way of figuring
out the leaf name.
Is possible to sort on the leaf name? Is it possible in XML 1.0? :)
Thank you!
- Scott
<xsl:template name="leaf-name">
<xsl:param name="string"/>
<xsl:choose>
<xsl:when test="substring-after($string,'.')">
<xsl:call-template name="leaf-name">
<xsl:with-param name="string"
select="substring-after($string,'.')"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$string"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list