RE: Problem with XSL and Namespace

Jeni and David,

I'm sorry. The xmlns="http://www.topicmaps.org/xtm/1.0/"; attribute is a
mistake.
I'll redefine my problem.

I'm making a stylesheet for generate another stylesheet. I'm using Saxon
6.5.2.
I want to create a root element in the XML document final (generated by
the second stylesheet) with a
namespace xmlns:xlink="http://www.w3.org/1999/xlink"; like above:

<root xmlns:xlink="http://www.w3.org/1999/xlink";>

But, if I define in the "mother" stylesheet this

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:axsl="http://www.w3.org/1999/XSL/TransformAlias";>
        <xsl:namespace-alias stylesheet-prefix="axsl"
result-prefix="xsl"/>
        <axsl:template match="/">
                <root xmlns:xlink="http://www.w3.org/1999/xlink";>
                        ...
                      <node>
                        <ref xlink:href="#products"/>
                      </node>
                        ...
                </root>
        </axsl:template>

the result XSL in "son" stylesheet is:

<axsl:stylesheet xmlns:axsl="http://www.w3.org/1999/XSL/Transform";
xmlns:xlink="http://www.w3.org/1999/xlink";
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="1.0">

   <axsl:template match="/">
      <root>
                ...
              <node>
                        <ref xlink:href="#products"/>
              </node>
                ...
        </root>
   </axsl:template>

The namespace xmlns:xlink="http://www.w3.org/1999/xlink"; was retired of
"root" element and put in "stylesheet" element.
Why? 
So, the final XML document generated is:

<root>
        ...
      <node>
                <ref xlink:href="#products"/>
      </node>
        ...
</root>

How can I to generate this?

<root xmlns:xlink="http://www.w3.org/1999/xlink";>
        ...
      <node>
                <ref xlink:href="#products"/>
      </node>
        ...
</root>

Thanks in advance,

------------------------------------
Giovani Rubert Librelotto
Ph.D. Student
Universidade do Minho
Braga - Portugal
grl(_at_)di(_dot_)uminho(_dot_)pt



> -----Original Message-----
> From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com 
> [mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of 
> Jeni Tennison
> Sent: Tuesday, October 15, 2002 4:36 PM
> To: Giovani Librelotto
> Cc: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
> Subject: Re: [xsl] Problem with XSL and Namespace
>
>
> Hi Giovani,
>
> > the result XSL in stylesheet "son" is:
> >
> > <xstm:stylesheet xmlns:axsl="http://www.w3.org/1999/XSL/Transform";
> > xmlns:xlink="http://www.w3.org/1999/xlink";
> > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="1.0">
> >
> >    <axsl:template match="/">
> >       <root xmlns="http://www.topicmaps.org/xtm/1.0/";>
> >
> > And in the final XML document generated is:
> >
> > <root>
> >   ..
> > </root>
> If so, then your processor is buggy. Given the stylesheet 
> that you have above, the <root> element that's generated in 
> the output should have two namespace nodes on it, one for xlink
> (http://www.w3.org/1999/xlink) and one for the default 
> namespace (http://www.topicmaps.org/xtm/1.0/). In order to 
> retain those nodes when serialized, it should look like:
>
> <root xmlns="http://www.topicmaps.org/xtm/1.0";
>       xmlns:xlink="http://www.w3.org/1999/xlink";>
>   ...
> </root>
>
> Which processor are you using? If you simplified your example 
> (which I guess you did, given that the prefix for the 
> stylesheet element hasn't been declared), perhaps you can 
> show us the actual 'son' stylesheet that you're using and we 
> can see whether there's something in it that would cause the 
> namespace nodes to disappear.
>
> Cheers,
>
> Jeni
>
> ---
> Jeni Tennison
> http://www.jenitennison.com/
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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