Hi Iris
Problem is that I want to get translated data from my external file
(translations.xml) in my xsl. I want to do this by passing
the founded
parameters (txtNode & txtLang), but that didn't work.
(cfr. <xsl:value-of select="$resource/$txtNode/$txtLang"/>)
When I pass my values without parameters it works! (cfr.
<xsl:value-of
select="$resource/AddressTitle/EN"/>)
How can I pass my parameters to get the correct node value of my file
Translations.xml ???
you can't use $parameters in XPath expressions like that. $txtNode contains
a string - would you expect to be able to do
"$resource/'AddressTitle'/'EN'?
You can use a predicate though:
select="$resource/*[local-name()=$txtNode]/*[local-name()=$txtLang]"
It's bad xml to encode information in the name of elements. Instead of
<Resource>
<AddressTitle>
<EN>Customer: </EN>
<NL>Klant: </NL>
<FR>Client: </FR>
</AddressTitle>
</Resource>
why not make the type of resource (Address Title, EN / NL / FR) into an
attribute?
wotcher,
Tom
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list