--- Àíäðåé Ñîëîí÷óê <solo at ibis dot odessa dot ua> wrote:
Hello All,
how calculate sum(x*y) ??
IF i try use sum() it say that need only node-list as argument....
I have xml
<root>
<data>
<x>2</x>
<y>3</y>
</data>
<data>
<x>5</x>
<y>6</y>
</data>
.....
<root>
--
Best regards,
Andrey Solo
mailto:solo(_at_)ibis(_dot_)odessa(_dot_)ua
Hi Andrey,
This is most easily done in a standard way by using the "foldl"
template from the FXSL library.
Given the following source xml:
------------------------------
<root>
<data>
<x>2</x>
<y>3</y>
</data>
<data>
<x>5</x>
<y>6</y>
</data>
<data>
<x>4</x>
<y>3</y>
</data>
</root>
This transformation:
-------------------
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:foldl-func="foldl-func"
exclude-result-prefixes="xsl foldl-func"
<xsl:import href="foldl.xsl"/>
<foldl-func:foldl-func/>
<xsl:variable name="vFoldlFun"
select="document('')/*/foldl-func:*[1]"/>
<xsl:output encoding="UTF-8" omit-xml-declaration="yes"/>
<xsl:template match="/">
<xsl:call-template name="foldl">
<xsl:with-param name="pFunc" select="$vFoldlFun"/>
<xsl:with-param name="pList" select="/*/*"/>
<xsl:with-param name="pA0" select="0"/>
</xsl:call-template>
</xsl:template>
<xsl:template match="foldl-func:*">
<xsl:param name="arg1" select="0"/>
<xsl:param name="arg2" select="/.."/>
<xsl:value-of select="$arg1 + $arg2/x * $arg2/y"/>
</xsl:template>
</xsl:stylesheet>
when applied on the above source xml document produces"
48
This is a more efficient solution than first copying the products into
a temporary node-set, then summing them (also possible with FXSL as:
sum (zipWith (*) list1 list2)
), because it does not have to produce a big temporary node-set with
all the products and then to have a second pass at this intermediate
list.
Hope this helped.
=====
Cheers,
Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL
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