RE: Looping using XSL

Actually this for each will go through every element in the source
document :) .//* would be every child of the context.

This issue actually should be pretty easy to solve.  I haven't tested
this, but this should work:

<xsl:template match="mood">
   <xsl:param name="iteration" select="number(rating)"/>

   <xsl:if test="$iteration &gt; 0">
      <DoStuff/>
      <xsl:apply-templates select=".">
         <xsl:with-param name="iteration" select="$iteration - 1"/>
      </xsl:apply-templates>
   </xsl:if>
</xsl:template>

HTH!

Dion

-----Original Message-----
From: Josh Campbell [mailto:josh(_at_)zype(_dot_)co(_dot_)nz] 
Sent: Tuesday, October 01, 2002 11:22 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Looping using XSL

Vasu Chakkera wrote:

> Doesnt <xsl:for-each select="//*[position() &lt;= rating]">
> iterate through all the child elements of the context node ., in this 
> case "mood"..
> so essentially since it has only one child element( "rating" ), It 
> should iterate only once irrespective of the condition *[position() 
> &lt;= rating]">
> so you xsl should produce only one line.
> <div class="moodbar"><img src="layout/global/pics/mood-red.gif" alt=""
> /></div>
> Vasu
That's what I've just found...though I appreciated the idea :-)
Sorry if the words 'looping' and 'iterate' have confused the issue but 
I'm not sure what else to call it.

I guess what's needed is some way of testing against the number in the 
rating node and write out the html line until the rating is equalled.

Josh



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