That looks like a date that was returned by SQL Server FOR XML clause(?)
I sometimes need to deal with those strings as well.
Here are some (MS) functions I use below (I'm sure there is a _much_
better way to do this, though):
<msxsl:script language="VBScript" implements-prefix="user">
<![CDATA[
function getAge(in_dteDate)
getAge = replace(in_dteDate, "T", " ")
getAge = dateDiff("d", getAge, now)
end function
function getDate(Node)
getDate = replace(Node, "T", " ")
getDate = formatDateTime(getDate, 1)
end function
function getTime(Node)
getTime = replace(Node, "T", " ")
getTime = formatDateTime(getTime, 3)
end function
]]>
</msxsl:script>
And then, for example:
<xsl:value-of select="user:getAge(string(@date))" />
Shenan
-----Original Message-----
From: Aniceto Lopez [mailto:aniceto(_at_)overthenet(_dot_)tv]
Sent: Tuesday, November 26, 2002 12:16 PM
To: xsl-list
Subject: [xsl] sort by date
Hi:
I'm trying to sort by date but the date format is
a little bit extrange:
<a4013-list>
<a4013 date="1998-01-03T00:00:00">FRUTAS</a4013>
<a4013 date="1999-12-03T00:00:00">FRUTAS</a4013>
<a4013 date="1999-05-03T00:00:00">FRUTAS</a4013>
<a4013 date="2001-12-03T00:00:00">FRUTAS</a4013>
<a4013 date="2001-12-03T00:00:00">FRUTAS</a4013>
<a4013 date="1999-07-03T00:00:00">FRUTAS</a4013>
<a4013 date="1999-12-03T00:00:00">FRUTAS</a4013>
<a4013 date="2002-12-03T00:00:00">FRUTAS</a4013>
<a4013 date="2002-07-03T00:00:00">FRUTAS</a4013>
</a4013-list>
the "T00:00:00" has no use but some one can point an
idea to get the desired sort by date?
thanks in advance
Ani
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list