If it were possible to do this in XSLT 1.0 without using the
xx:node-set() extension, then the xx:node-set() extension would not have
been invented. You're out of luck, I'm afraid. Unless of course you use
an XSLT 1.1 or XSLT 2.0 processor.
Michael Kay
Software AG
home: Michael(_dot_)H(_dot_)Kay(_at_)ntlworld(_dot_)com
work: Michael(_dot_)Kay(_at_)softwareag(_dot_)com
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Laura Jenkins
Sent: 18 November 2002 17:12
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] looping through Elements stored in a variable..
Hello people,
i have the following xsl structure
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
<xsl:variable name="univ-var">
<University-List>
<University id = "1"> University1</University>
<University id = "2"> University2</University>
<University id = "3"> University3</University>
<University id = "4"> University4</University>
</University-List >
</xsl:variable>
<!-- i want to iterate through this variable without usiing
the extension nodeset..-->
<!-- something along the lines of .. -->
<xsl:for-each select="$place-var/placements/placement">
<xsl:value-of select="."/>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
What i was doing obviousl;y does not work because it needs to
be a nodeset. Can any one tell me how to do this without
using the extension : nodeset. Its is MANDATORY that I DO
NOT USE the extension nodeset. Thanks
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