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Re: XPath expression for finding out the depth of a given node?

2002-11-17 13:25:07
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On Sunday 17 November 2002 12:10, Peter Davis wrote:
count(ancestor-or-self::*)

On second thought, you would need to change that to 
count(ancestor-or-self::node()), to be consistant with text() and other 
nodes.  Or, you could just do count(ancestor::*)+1.  Hope you get the idea.

- -- 
Peter Davis
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