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Re: sequential grouping question

2002-11-17 08:28:29
Thank you Joerg !

it's beautiful, I realizedthis it's 'Muench method'
thank you for the leads. although the grouping the
substring is poor, I can make a temp tree with these
strings.

regards.
Paul


--- Joerg Heinicke <joerg(_dot_)heinicke(_at_)gmx(_dot_)de> wrote:
Hello Paul,

it's a really poor XML for grouping. You must group
the <xs:element/> by 
their preceding- or
following-sibling::xsl:element[not(starts-with(@ref,

'snoopy'))]. Grouping by a substring must be poor.
Do you really have no 
influence on the input?

<xsl:key name="elements" match="xs:element" 
use="generate-id((preceding-sibling::xs:element |
self::xs:element) 
[not(starts-with(@ref, 'snoopy'))][last()])"/>

<xsl:template match="xs:sequence">
   <xsl:apply-templates select="key('elements', '')"
mode="start"/>
   <xsl:apply-templates select="key('elements', '')"
mode="end"/>
---
   <xsl:apply-templates
select="xs:element[not(starts-with(@ref, 
'snoopy'))]" mode="group"/>
</xsl:template>

<xsl:template match="xs:element" mode="group">
   <xsl:apply-templates select="." mode="start"/>
   <xsl:apply-templates select="." mode="end"/>
   <xsl:apply-templates select="key('elements', 
generate-id())[generate-id() !=
generate-id(current())]" mode="start"/>
   <xsl:apply-templates select="key('elements', 
generate-id())[generate-id() !=
generate-id(current())]" mode="end"/>
---
</xsl:template>

<xsl:template match="xs:element" mode="start">
   <xsl:value-of select="@ref"/> starts
</xsl:template>

<xsl:template match="xs:element" mode="end">
   <xsl:value-of select="@ref"/> ends
</xsl:template>

Output:

snoopy-a starts
snoopy-b starts
snoopy-c starts
snoopy-a ends
snoopy-b ends
snoopy-c ends
---
Harry-GROUP starts
Harry-GROUP ends
snoopy-d starts
snoopy-e starts
snoopy-d ends
snoopy-e ends
---
MickeyMouse-GROUP starts
MickeyMouse-GROUP ends
snoopy-f starts
snoopy-f ends
---

Regards,

Joerg


hb wrote:
Hi

stuck by belowed grouping problem, Is it possible
to
give any suggestion ? 

++++++++++++ begin schema +++++++++++

<xs:element name="LETTERMSG">
    <xs:complexType>
            <xs:sequence>
                    <xs:element ref="snoopy-a"/>
                    <xs:element ref="snoopy-b"/>
                    <xs:element ref="snoopy-c"/>
                    <xs:element ref="Harry-GROUP"/>
                    <xs:element ref="snoopy-d"/>
                    <xs:element ref="snoopy-e"/>
                    <xs:element ref="MickeyMouse-GROUP"/>
                    <xs:element ref="snoopy-f"/>
            </xs:sequence>
    </xs:complexType>
</xs:element>
</xs:schema>
++++++++++++ end schema +++++++++++

++++++++++++ begin output +++++++++++
snoopy-a goto room(1)
snoopy-b goto room(2)
snoopy-c goto room(3)
snoopy-a back form room(1)
snoopy-b back form room(2)
snoopy-c back form room(3)

Hacked Harry-GROUP, putinto safetybox(1)
get Harry-GROUP form safetybox(1)

snoopy-d goto room(1)
snoopy-e goto room(2)
snoopy-d back form room(1)
snoopy-e back form room(2)

Hacked MickeyMouse-GROUP, putinto safetybox(1)
get MickeyMouse-GROUP form safetybox(1)

snoopy-f goto room(1)
snoopy-f back form room(1)
+++++++++++ end output +++++++++++

the desired output need to be
1) by SEQUENCE
2) by different TYPE(group or simple element)

(it's dynamic because, the style sheet have to
apply
different schema of LETTERMSG)

Is there any idea ?

Many thanks
Paul


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