I am trying to find a way to create a generic xsl sorting function that
takes 5 parameters, which are the names of the nodes to sort.
I dont understand how to pass parameters to an xsl stylesheet, but basically
i just want a simple sorting function that sorts the xml and returns a
sorted version of the xml using xsl:copy.
So far this is what i got:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xsl:template name="GenericSort">
<!-- The sort fields -->
<xsl:param name="SortField0" select="" />
<xsl:param name="SortField1" select="" />
<xsl:param name="SortField2" select="" />
<xsl:param name="SortField3" select="" />
<xsl:param name="SortField4" select="" />
<xsl:copy >
<xsl:apply-templates>
<xsl:sort select="$SortField0" />
<xsl:sort select="$SortField1" />
<xsl:sort select="$SortField2" />
<xsl:sort select="$SortField3" />
<xsl:sort select="$SortField4" />
</xsl:apply-templates>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
But my problem is, it doesnt work... i want the first sort field
(sortfield0) to sort on the global node-set (ancestor::*[next-sibling()]) ??
Any help will be appreciated, thanks
MoMad
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list