Saxon's output when you use xsl:namespace-alias is inelegant but the
stylesheet that it produces is precisely equivalent to the one that you
want.
It will be improved in the next version.
Michael Kay
Software AG
home: Michael(_dot_)H(_dot_)Kay(_at_)ntlworld(_dot_)com
work: Michael(_dot_)Kay(_at_)softwareag(_dot_)com
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Timothy Larson
Sent: 14 November 2002 18:28
To: XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] With Saxon7.2, can an aliased namespace prefix
be excludedfrom the output?
With Saxon version 7.2, I am trying to apply a stylesheet to
a stylesheet. Is there any way to exclude the aliased
namespace prefix from the output?
In the sample below I am trying to get rid of the output line:
xmlns:x="http://www.w3.org/1999/XSL/Transform";
Sample source stylesheet:
<?xml version="1.0"?>
<xsl:stylesheet version="2.0"
xmlns:xsl = "http://www.w3.org/1999/XSL/Transform";>
</xsl:stylesheet>
Sample stylesheet to apply to the source stylesheet:
<?xml version="1.0"?>
<xsl:stylesheet version="2.0"
xmlns:xsl = "http://www.w3.org/1999/XSL/Transform";
xmlns:x = "http://www.w3.org/1999/XSL/TransformAlias";
exclude-result-prefixes="x">
<xsl:namespace-alias stylesheet-prefix="x" result-prefix="xsl"/>
<xsl:template match="/">
<xsl:copy>
<x:stylesheet>
<x:template m="/"><x:value-of select="test"/></x:template>
</x:stylesheet>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Output produced:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
xmlns:x="http://www.w3.org/1999/XSL/Transform";
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template m="/"><xsl:value-of
select="test"/></xsl:template> </xsl:stylesheet>
Output disired:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template m="/"><xsl:value-of
select="test"/></xsl:template> </xsl:stylesheet>
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